Torsion of a Beam with the Square Cross-Section
Let us consider a beam with the square cross-section. The length of the side of a square is a. Length of the beam is L (see figure).
The beam is subjected to the externally applied torque Mt. The torque is applied at the right end of the beam, the left end of the beam is rigidly clamped.
The finite element model with applied loads and restraints |
Let us use the following initial data: length L of the beam is 1.5 m, the length of the side of a square a is 0.050 m, the magnitude of the applied torque Mt is 1000 N-m.
Material characteristics: E = 2.0E+011 Pa, ν = 0.29.
To find the angle of twist, let us use the following relation:
,
where G=E/2(1+ν) – shear modulus, Jp=βa4 – polar moment of inertia of the square cross-section, β= 0.1406.
Thus, ϕ= 2.2168E-002 rad.
The maximal displacement is calculated by the following formula:
Thus, Δu = 7.8371E-004 m.
The maximal shear stress τ max is calculated by the following formula:
where α= 0.208
Thus, τ max = 3.8462E+007 Pa.
After carrying out calculation with the help of AutoFEM, the following results are obtained:
Table 1.Parameters of finite element mesh
Finite Element Type |
Number of nodes |
Number of Finite Elements |
quadratic tetrahedron |
24449 |
14862 |
Table 2. Result "Displacement"
Numerical Solution |
Analytical Solution |
Error δ = 100%* | Δu* - Δu | / | Δu | |
7.7619E-004 |
7.8371E-004 |
0.96 |
Table 3. Result "Shear Stress"
Numerical Solution |
Analytical Solution |
Error δ = 100%*| τmax* - τmax | / | τmax | |
4.0144E+007 |
3.8462E+007 |
4.37 |
|
Conclusions:
The relative error of the numerical solution compared to the analytical solution is 0.96% for displacements and 4.37% for stresses when using quadratic finite elements.
*The results of numerical tests depend on the finite element mesh and may differ slightly from those given in the table.
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